t42 15" screen dimensions

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elmokiddo
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t42 15" screen dimensions

#1 Post by elmokiddo » Mon Nov 22, 2004 7:19 pm

Hi, I am doing some research on T42s and had a quick question, does anyone have the viewable screen dimensions L x W of a 15" T42 in mm?

I tried searching but could only find the dimensions of the whole unit.

Thanks,
Elmo

BccKiller
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Screen Size

#2 Post by BccKiller » Mon Nov 22, 2004 7:40 pm

37.9 CM
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elmokiddo
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#3 Post by elmokiddo » Mon Nov 22, 2004 7:43 pm

Thanks, I am guessing that is the length...would you have the width? (or viceversa)

Elmo

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Wrong Info

#4 Post by BccKiller » Tue Nov 23, 2004 12:17 am

Sorry, I gave you the wrong information

I don't have ruler with me right now. Based on my tape meaurement, the screen size is 9"(W) x 12"(L). I think you should not have a problem to convert it to MM. The size that i gave it to you at first is the screen size in CM.
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beeblebrox
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#5 Post by beeblebrox » Tue Nov 23, 2004 3:47 am

I don't want to be rude,
but if the screen is 15" and has a ratio of 4:3, then why don't you use your brain cells and make a quick back-on-the-envelope calculation to get the widht and height!

It is grammar school mathematics!
...never mind!

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#6 Post by gcchatel » Tue Nov 23, 2004 9:22 am

haha beeblebrox, i was just thinking the same thing...simple geometry

lets see here, recall the 3, 4, 5 triangle rule...well the 4:3 access ratio means we have one of those, the hypotenuse is 15 so that is 5*3 so simply multiply 3*3 for a height of 9 and 4*3 for a width of 12. And you thought you would never use that stuff :wink:
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#7 Post by Ghostrider » Tue Nov 23, 2004 10:06 am

gcchatel wrote:haha beeblebrox, i was just thinking the same thing...simple geometry

lets see here, recall the 3, 4, 5 triangle rule...well the 4:3 access ratio means we have one of those, the hypotenuse is 15 so that is 5*3 so simply multiply 3*3 for a height of 9 and 4*3 for a width of 12. And you thought you would never use that stuff :wink:
What has "5*3=15" with "a^2+b^2=c^2" (a²+b²=c²) to do???
c=15" ... but you can't solve it without applying that all pixels have the same height and width and constant spaces on all sides between them and that their number fulfill the 4:3 ratio.

I have seen some CRTs with the same Size (21") and advertised 4:3 ratio but they do not have the same height and width - they just display the 4:3 resolutions. (they can display any resolution because they are CRTs, of course)
I'd be careful making jokes of someone who asks for the width and height of the real displays.

BTW: I'd like to see a correct solution of the equation above... I study physics and can do it... but the calculations posted above were not that good ;)
Regards,
Ghostrider

kano
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#8 Post by kano » Tue Nov 23, 2004 12:13 pm

Ghostrider wrote:[BTW: I'd like to see a correct solution of the equation above... I study physics and can do it... but the calculations posted above were not that good ;)
Solution is simply, because for native resolution 1600x1200 (4:3) we have 2 equations:
a²+b²=c²
3a=4b
The final results are:
a=4/5 c
b=3/5 c

For popular LCD monitors with native resolution 1280x1024 (5:4) the second equation will be:
4a=5b
and adequately:
a=5/sqrt(41) c
b=4/sqrt(41) c

Regards, KaNo
Last edited by kano on Tue Nov 23, 2004 1:26 pm, edited 1 time in total.

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#9 Post by Ghostrider » Tue Nov 23, 2004 12:56 pm

That looks better ;)

But you also assume that all pixels are perfect squares not just rectangular and that the columns and rows of pixels have exactly the same spaces between each other. Well, they are very similar but if (caused by any technical reason or the manufactoring process...) the ratio of the pixel edges would be just 1:1.01 you could not calculate it that way.
This calculation is good enough to estimate the size but measuring the display size is the safe way to confirm it.
Regards,
Ghostrider

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